16. Another student calculated the R of a fifth objective lens as described in Activity 3. He determined that for this fifth objective lens, R = 1,830 nm. Accordingly, the NA of this lens was most likely closest to which of the following values ?
Your Answer is
Correct Answer is F
Explanation
Looking at table 3, R=1830 nm indicates that NA is between 0.10-0.25, so 0.15 of option F fits this range