49. Counting repetition, how many prime factors appear in any prime factorization of the integer (63)5 ?

(Note: For example, counting repetition, 5 prime factors appear in the prime factorization of 588 as 2 · 2 · 3 · 7 · 7.)

Answer and Explanation

Your Answer is

Correct Answer is B

Explanation

The prime factor of 63 is 3*3*7, a total of 3; so the number of prime factors of 635 is 3*5=15, choose B