47. Given constants c, d, m, and n such that x2 + mx + c has factors of (x + 2) and (x + 4) and x2 + nx + d has factors of (x + 3) and (x + 7), what is mn ?

Answer and Explanation

Your Answer is

Correct Answer is D

Explanation

x² + mx + c = (x+2) (x+4), we know that m=6;

x² + nx + d = (x+3) (x+7), we know n=10.