1. According to Table 1, in Trial 5. what was the equilibrium concentration of Z ?
Your Answer is
Correct Answer is B
Explanation
Through the explanation of brackets[ ] under the formula in the article, we understand that [Z] in table 1 is the equilibrium concentration of Z, so directly look at trail 5 of table 1, [Z] should be 0.50 mol/L< /p>