22. Based on the results of Experiment 1, the pI of leucine is approximately:
Your Answer is
Correct Answer is H
Explanation
According to table 1, we can see that only when ph=pI, the net charge (net charge) will be equal to 0, and the form of expression is that leucine is right in the middle of the paper strip, as shown in trial 3, so the pH should be 6.0