Passage V

The higher a gasoline's octane number (ON), the more smoothly the gasoline burns, lessening engine damage. Sulfur (S), naturally present in gasoline, damages exhaust systems in cars. Table 1 gives the ON and S content of 6 gasolines (Fuels A-F).

Figures 1 and 2 show the decrease in ON resulting from using Methods 1 and 2, respectively, to reduce a gasoline's S content from a given initial value to a given final value. Consider a gasoline having an ON of 90.00 and an S content of 100 ppm. If Method 1 is used to reduce the S content to 25 ppm, Point A in Figure 1 shows that the decrease in ON will be 0.35, so the ON will decrease to 89. 65 (because 90.00 - 0.35 = 89.65).

26. Suppose a chemist used Method 1 to reduce the S content of Fuel D and of Fuel F each to 10 ppm. Based on Table 1 and Figure 1, after the reduction, which fuel would have the higher ON?

Answer and Explanation

Your Answer is

Correct Answer is H

Explanation

Looking at table 1, the S content of fuel D is 75 ppm, corresponding to figure 1, when the abscissa is 10ppm, the ordinate decrease in ON corresponding to the curve of 75ppm is about 0.6, that is to say, the value of ON changes For 86.9-0.6=86.3;

Look at the S content of fuel F listed in table 1 is 100 ppm, corresponding to the curve of 100 ppm in figure 1, when the abscissa is 10 ppm, the ordinate It is 0.75, that is to say, the value of ON becomes 92-0.75=91.25, and the H option is relatively mild with these two values