38. Which of the following, if true, would have been a flaw in the design of Experiment 2?
Your Answer is
Correct Answer is J
Explanation
For general knowledge questions, use the method of elimination.
If the average conductivity of option F is greater than 40, it does not mean that there is any flaw in the experimental design;
The range of tool degrees for measuring conductivity in option G is 0-120, as can be seen from table 2 , all the experimental results are within this range, there is no problem at all with this tool;
There is no problem with the concentration of solution 5 in the H option being lower than that of solution 6, and the concentration of each solution in the test is different;
If the freezing point of some solutions mentioned in option J is lower than -20°C, then the second line of the text part of Experiment 2 says that all solutions use a cold bath at -20°C, which will cause some solutions to No solid is formed. So you should choose J