Question 57 Answer and Explanation _ACT June 2008 Form 66C Math Section

Question 57 Answer and Explanation _ACT June 2008 Form 66C Math Section

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57. When x ≠ 5 and x ≠ -5, $\frac{2x}{{x}^{2}-25}+\frac{2x}{5-x}$ is equivalent to:

A. $\frac{-2{x}^{2}}{{x}^{2}-25}$

B. $\frac{{-2x}^{2}-8x}{{x}^{2}-25}$

C. $\frac{{4x}^{2}-10x}{{x}^{2}-25}$

D. $\frac{-10x}{{x}^{2}-25}$

E. $\frac{2x+12x}{{x}^{2}-25}$

Answer and Explanation

Your Answer is

Correct Answer is B

Explanation