50. If the function f satisfies the equation f (x + y) = f (x) + f ( y) for every pair of real numbers x and y, what is(are) the possible value(s) of f (0) ?
Answer and Explanation
Your Answer is
Correct Answer is K
Explanation
So f( x+y )=f( x )+f( y) so f( 0)=f( 0 )+f( 0). So f( 0)=0.